Sam is 9 years older than nick. 7 years ago he was 4 times as old as nick. How old is sam now? x = Nick's age now x + 9 = Sam's age now {Sam is 9 years older than Nick} x  7 = Nick's age 7 years ago x + 2 = Sam's age 7 years ago {subtracted 7 from age now} x + 2 = 4(x  7) {seven years ago, Sam was four times Nick} x + 2 = 4x  28 {used distributive property} 3x = 30 {added 28 and subtracted x from each side} x = 10 {divided each side by 3} x + 9 = 19 {substituted 10, in for x, into x + 9} Sam is 19  Algebra House Comments are closed.

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